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Verified Answer :

Nirina7

if we assume that S is  as tangent point, we can have the following formula:
(arcRS - arcSQ)/2 = ∠RPS= (arc RS - 84°) /2=26°
it means   arc RS - 84° = 52°, and then meas arc RS = 52+84=136°



calculista

Answer:

\(arc\ RS=136\°\)

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The measurement of the external angle is the semi-difference of the arcs which comprises

In this problem

m∠RPS=\(26\°\) ------> external angle

so

m∠RPS=\(\frac{1}{2}(arc\ RS-arc\ SQ)\)

we have

m∠RPS=\(26\°\)

\(arc\ SQ=84\°\)

substitute the values

\(26\°=\frac{1}{2}(arc\ RS-84\°)\)

Solve for arc RS

\(52\°=(arc\ RS-84\°)\)

\(arc\ RS=52\°+84\°=136\°\)



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