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Verified Answer :

bcalle

20y^2 + 3y - 2
20 -2 = -40
factors of -40 that subtract to give you 3
8
-5 = -40
8 + (-5) = 3
20y^2 -5y + 8y -2
5y( 4y - 1) +2(4y -1)
(4y - 1) ( 5y + 2)

Answer:

\((5y+2)(4y-1)\)

Step-by-step explanation:

Given: \(20y^2+3y-2\)

Factor: Middle term splitting

We have to factor the quadratic equation.

\(\Rightarrow 20y^2+3y-2\)

\(\Rightarrow 20y^2+8y-5y-2\)

Make group and factor each group

\(\Rightarrow (20y^2+8y)-(5y-2)\)

\(\Rightarrow 4y(5y+2)-1(5y+2)\)

\(\Rightarrow (5y+2)(4y-1)\)

Hence, The factors are \((5y+2)(4y-1)\)

Please see the attachment for grid factor.

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