Answer: The midpoint of line segment AB is,
\((4,3)\)
Step-by-step explanation:
Since, the coordinates of the midpoint of a line segment having the endpoints \((x_1,y_1)\) and \((x_2,y_2)\) are,
\((\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\)
Thus, the coordinates of midpoint of the line segment AB having endpoints A(9, 8) and B(-1, -2) are,
\((\frac{9+(-1)}{2},\frac{8+(-2)}{2})\)
\(=(\frac{9-1}{2}, \frac{8-2}{2})\)
\(=(\frac{8}{2}, \frac{6}{2})\)
\(=(4,3)\)
