The length of a rectangle is 3 more than twice the width. The area of the rectangle is 119 square inches. What are the dimensions of the rectangle?
If x = the width of the rectangle, which of the following equations is used in the process of solving this problem?
2x^ 2 + 3x - 119 = 0
3x ^2 + 3x - 119 = 0
6x ^2 - 119 = 0
If x = the width of the rectangle, which of the following equations is used in the process of solving this problem?
2x^ 2 + 3x - 119 = 0
3x ^2 + 3x - 119 = 0
6x ^2 - 119 = 0