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Verified Answer :

ahonyek

So the first one is 16t^4/8t
16/8=2 
t^4/t can be written as tttt/t 
t/t=1
so t^4/t =ttt1=t^3
Thus 16t^4/8t= 2t^3

Try the other problems with the same technique

baabaagreysheep

When you divide indices (exponents), you subtract. The numbers act in the normal way:
5. 16t^4/8t
16 ÷ 8 = 2
4 - 1 = 3
answer = 2t^3

6. x^6y^14/x^4y^9
6 - 4 = 2
14 - 9 = 5
answer = x^2y^5

7. 3^4x^4/3x^2
3^4 = 3 × 3 × 3 × 3 = 81
81 ÷ 3 = 27
4 - 2 = 2
answer = 27x^2

I hope this helps!