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A carpenter built three bookcases, A, B and C, to stand next to each other along a wall. The total length of the wall is 456 centimeters. The carpenter will build two more bookcases, D and E, along the same wall. These two book cases will have equal widths. The widths of bookcases A, B and C are A 132 cm, B 94 cm, C 108 cm. What is the width of D and E?

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calculista

Answer:

The width of bookcase D is 61 cm

The width of bookcase E is 61 cm

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Sum the widths of the three bookcases A, B and C

\(132+94+108=334\ cm\)

step 2

Subtract the sum of the three bookcases A,B and C from the total length of the wall

\(456-334=122\ cm\)

step 3

Divide that answer in step 2 by 2, and that will let you know the widths of D and E, because they may have equal widths

\(122/2=61\ cm\)

therefore

The width of bookcase D is 61 cm

The width of bookcase E is 61 cm

View image calculista
lamine0110

Answer:61

Step-by-step explanation:both are 61 cm

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