bewellplus.gsu.edu
katgatayajairra katgatayajairra
  • 11-02-2015
  • Mathematics
Answered

How do you do 4x^2+3x-10=0

Verified Answer :

konrad509
konrad509 konrad509
  • 11-02-2015

\(4x^2+3x-10=0\\ 4x^2+8x-5x-10=0\\ 4x(x+2)-5(x+2)=0\\ (4x-5)(x+2)=0\\ x=\dfrac{5}{4} \vee x=-2\)

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