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B1.37 10-1 mol of iridium

Answer: b. [tex]1.37\times 10^{-1}moles[/tex]

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number \(6.023\times 10^{23}\) of particles.

To calculate the moles, we use the equation:

\(\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}\)

\(\text{Number of moles of iridium}=\frac{26.4g}{192g/mol}=0.137moles=1.37\times 10^{-1}moles\)

Thus \(1.37\times 10^{-1}moles\) of iridium are in 26.4 g of iridium.

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