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baileysmall
Answered

1.) What is the vertex of the quadratic function y=x^2-4x-1

2.) What is the solution set for the quadratic function y=x^2-4x-21

3.) What are the solutions to the quadratic equation (x+9)(x-1)=0

4.) What are the zeros for the quadratic function f(x)=x^2+10+25

Verified Answer :

calebwhitaker
  1. Solve by differentiation (Derivative = 0 at the vertex)

    dy/dx= 2x-4

    0=2x-4

    0=2(x-2)

    x=2

    when x=2 y=-5

    therefore vertex (2,-5)
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