Calculate the pH of a 1.840 M solution of HNO3
Data:log10(1.8) ≈ 0.25Solving:\(pH = - log[H_{3} O^+]\)\(pH = - log1.840 (mol/L)\)\(pH = - log1.8*10^3\)\(pH = 3 - 0.25\)\(\boxed{\boxed{pH = 2.75}}\end{array}}\qquad\quad\checkmark\)Note:. The pH <7, then we have an acidic solution.
