ln(t-1)^2=3 Solve the equation
\(\ln(t-1)^2=3\)\(2\ln(t-1)=3\)\(\ln(t-1)=\dfrac32\)\(e^{\ln(t-1)}=e^{3/2}\)\(t-1=e^{3/2}\)\(t=1+e^{3/2}\)
