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Calculus help please!!! Click the link to see the integral.

\(\int\limits { \frac{cosx}{ \sqrt{sinx} } } \, dx\)

Verified Answer :

noice

ook, so use u subsitution

remember that dy/dx(sin(x))=cos(x)

u=sin(x)
du/dx=cos(x)
du=cos(x) dx
so then

\(\int\limits{ \frac{cos(x)}{ \sqrt{sin(x)} } } \, dx\)
replace
\(\int\limits{ \frac{1}{ \sqrt{u} } } \, du\)
we do some stuff
\(\int\limits{ u^ \frac{-1}{2} } } \, du\)
\(\frac{u^ \frac{1}{2} }{ \frac{1}{2} }\)
\(2 \sqrt{u}\)
u=sin(x)
\(2 \sqrt{sin(x)}\)