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Verified Answer :

Just use unit analysis, but you'll have to balance the equation first
3H2-> 2NH3 (Other products and reactants omitted)
3.64 g/ 2 (g/mol) 2/3 17= 20.6 g of NH3

The number of grams of \(NH_3\) that could be produced is 20.6g.

Given that,

  • There are 3.64g of \(H_2\).
  • There is the chemical equation of \(N_2(g) +3H_2(g) \rightarrow 2NH_3 (g)\).

Based on the above information, the calculation is as follows:

N2(g) +3H2(g)-> 2NH3 (g)

28g     6g             34g

Now

\(6gH_2 \rightarrow 34g NH_3\)

So for 3.64g should be

\(= 34\times 3.6\div6\)

= 20.6g

Therefore we can conclude that the number of grams of \(NH_3\) that could be produced is 20.6g.

Learn more: brainly.com/question/943897



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