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pinageee
pinageee
16-02-2017
Mathematics
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Sec^2x-1/sec^2x=sin^2x
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LammettHash
LammettHash
16-02-2017
\(\dfrac{\sec^2x-1}{\sec^2x}=1-\dfrac1{\sec^2x}=1-\cos^2x=\sin^2x\)
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