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emipoland
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A 40kg-skier starts at the top of a 12-meter high slope. At the bottom, she is traveling 10 m/s. How much energy does she lose to friction


A.She doesn't lose any because mechanical energy is always conserved


B.4,704 J


C.2,000 J


D.2,704 J

Verified Answer :

Energy at top = U = mgh = 40 9.8 12 = 4704 J

Energy at bottom = 1/2 mv² = 1/2 40 10² = 4000 / 2 = 2000 J

Energy Lost = Final - Initial = 4704 - 2000 = 2704 J

In short, Your Answer would be Option D

Hope this helps!

blueaqua73

I took this quiz the answer was D.2,704 J. Just trying to help.

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