First find the common multiple, the number that is divisible by 9, 10, and 11.
This is 91011 = 990
Next notice that by using factoring, we can subtract either 9,10,11 and the result will be divisible by that number.
\(\frac{9*10*11 -11}{11} = \frac{11(9*10 -1)}{11} = 9*10 -1\)
This works for 10 as well as 9.
Therefore the 3 consecutive integers are:
990-11, 990-10, 990- 9
979, 980, 981
