\((x-h)^2+(y-k)^2=r^2\)
center is (h,k) and radius is r
so
given center=(-3,2)=(h,k)
\((x-(-3))^2+(y-2)^2=r^2\)
\((x+3)^2+(y-2)^2=r^2\)
find r^2
ok, (6,4) is a point
sub 6 for x and 4 for y and evaluate
\((6+3)^2+(4-2)^2=r^2\)
\((9)^2+(2)^2=r^2\)
\(81+4=r^2\)
\(85=r^2\)
the equation is
\((x+3)^2+(y-2)^2=85\)
