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What is the area of a triangle whose vertices are D(3,3) , E(3,−1) , and F(−2,−5)?

?= Unit ^2

Verified Answer :

length of DE = 3-(-1) = 4

SIDE DE is a vertical line 

horizontal distance between E and F is  3 - (-2) = 5

So the area of triangle DEF = 0.5 4 5 = 10 sq units

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