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Verified Answer :

Let \(a\) be the first digit and \(b\) the second. Then the number is \(x=10a+b\). The sum and difference of the two digits is 6, which means

\(\begin{cases}a+b=6\\a-b=6\end{cases}\implies a=6,b=0\)

which means the number is \(x=6\times10+0=60\)