bewellplus.gsu.edu
Anonymous Anonymous
  • 04-02-2015
  • Mathematics
Answered

Can some one help me? Please!

Can some one help me? Please! class=

Verified Answer :

konrad509
konrad509 konrad509
  • 04-02-2015

\(\frac{1}{3}(n+3)=6\\ n+3=18\\ n=15 \Rightarrow C\)

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VzDeath
VzDeath VzDeath
  • 04-02-2015

\(\frac{1}{3}(n+3)=6 \\ \frac{1}{3}n+1=6 \\ -1\ \ \ \ -1 \\ \frac{1}{3}n=5 \\ n=\boxed{15}\)

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