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a country population in 1993 was 94 million in 1999 it was 99 million estimate the population in 2005 using the exponential growth formula round your answer to the nearest million p=aekt

Verified Answer :

wolf1728

k = ln(ending amt/bgng amount)/6 years
k = ln(99,000,000/94,000,000) / 6 years
k = ln(



1.0531914894



) / 6 years
k =



0.0518250679



/ 6
k =



0.0086375113

Final population = bgnge^kyears
Where "e" is the mathematical constant 2.718281828
Final population = 94,000,000e^0.008637511312
Final population = 94,000,000e^0.1036501356




Final population = 94,000,000



1.1092123132






Final population =



104,265,957






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