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Verified Answer :

The equation of the line passing through the points \((x_1,y_1)\) and \((x_2,y_2)\) is

\(\frac{x-x_1}{y-y_1} =\frac{x_2-x_1}{y_2-y_1}\). Here \(\frac{y_1-y_1}{x_2-x_1}\) is the slope of the line.

Substituting numerical values,

\(\frac{x-2}{y+3} =\frac{4-2}{2+3} \\
\frac{x-2}{y+3} =\frac{2}{5} \\
5x-10=2y+6\\
5x-2y-16=0\)

The equation of the line in standard form is \(5x-2y-16=0\).

Answer:

5x - 2y = 16

Step-by-step explanation:

Slope = 5/2

b = -8

Slope-intercept form: y = 5/2x -8


Standard: 5x - 2y = 16