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jhernandez5167 jhernandez5167
  • 02-02-2015
  • Mathematics
Answered

solve for x

log(x–4)+log(x+3)=2logx

Verified Answer :

konrad509
konrad509 konrad509
  • 02-02-2015

\(D:x-4>0 \wedge x+3>0 \wedge x>0\\ D:x>4 \wedge x>-3 \wedge x>0\\ D:x>4\\\\ \log(x-4)+\log(x+3)=2\log x\\ \log(x-4)(x+3)=\log x^2\\ (x-4)(x+3)=x^2\\ x^2+3x-4x-12=x^2\\ -x=12\\ x=-12\\ -12 ot\in D\\ \Downarrow\\ \boxed{x\in\emptyset}\)

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