Verified Answer :

4[2a+b]/c[b+2a] = 4/c.

\(\frac{8a+4b}{bc+2ac}\)
this when factorised gives\(\frac{4(2a+b)}{c(2a+b)}\)
2a+b on the numerator cancels 2a+b on the denominator
it will give\(\frac{4}{c}\)*1
\(\frac{4}{c}\)

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