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Verified Answer :

to find the sum:

2(3t-4) - (t^2 + 2) - 4t(t-1)

6t - 8 - t^2 - 2 - 4t^2 + 4

6t - 8 - 5t^2  + 2

-5t^2 + 6t - 6

by the sum of roots and product of roots formulae

ax^2 + bx + c

x + y  = \(\frac{-6}{-5}\)

x + y = \(\frac{6}{5}\)

xy = \(\frac{-6}{-5}\)

xy = \(\frac{6}{5}\)

x - y =