What is the quotient (125 – 8x3) ÷ (25 + 10x + 4x2)?
Your answer is:
(125 - 8x^3) / (25 + 10x + 4x^2) = - ((2x - 5) * (4x^2 + 10x + 25)) / (4x^2 + 10x + 25) = - (2x - 5) = - 2x + 5
The correct result would be - 2x + 5.
Answer:
\(-2x+5\)
Step-by-step explanation:
The given equation is:
\(\frac{125-8x^3}{25+10x+4x^2}\)
On dividing and simplifying the above equation, we get
=\(\frac{-(2x-5)(4x^2+10x+25)}{4x^2+10x+25}\)
Solving the like terms, we get
=\(-(2x-5)\)
=\(-2x+5\)
which is the required quotient of the given equation.