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Determined the quadrant for an angle with the following characteristics: cotθ>0 and cscθ>0.

AQuadrant I
BQuadrant II
CQuadrant III
DQuadrant IV

Verified Answer :

\(\csc\theta=\dfrac1{\sin\theta}>0\implies\sin\theta>0\)

This happens whenever the terminal point of \(\theta\) lies in either the first or second quadrants.

Meanwhile,

\(\cot\theta=\dfrac1{\tan\theta}=\dfrac{\cos\theta}{\sin\theta}>0\implies\cos\theta>0\)

since you already know sine is positive. Cosine is positive when the angle lies in the first or fourth quadrant.

Sine and cosine are both positive only when \(\theta\) is the first quadrant, which means this angle's terminal point lies in the first quadrant (A).