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1 mole of a substance contains 6.022x10^23 "units" of that substance.

So 0.187 mol of Na+ is 1.13x10^23 ions (6.022x10^23 x 0.187).

Answer : The number of ions present in 0.187 mole of sodium ions are, \(1.163\times 10^{23}\)

Solution : Given,

Moles of sodium ions = 0.187 moles

As we know that

1 mole of substance contains \(6.22\times 10^{23}\) number of ions

So, 0.187 moles of substance contains \(0.187\times (6.22\times 10^{23})=1.163\times 10^{23}\) number of ions

Therefore, the number of ions present in 0.187 mole of sodium ions are, \(1.163\times 10^{23}\)


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