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Verified Answer :

\(\frac { 3ax }{ 5 } -4c=\frac { ax }{ 5 }\)
First multiply both sides by 5:
\(5\cdot (\frac { 3ax }{ 5 } -4c)=5\cdot \frac { ax }{ 5 } \\ 3ax-20c=ax\)
then take the ax to the other side :
\(3ax-20-ax=0\) and simplify:
\(2ax-20c=0\) factor:
\(2(ax-10c)=0\\ ax-10c=0\\ ax=10c\\ x=\frac { 10c }{ a }\)

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