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Verified Answer :

The given operation involves just swapping the two rows, so carrying out \(R_1\leftrightarrow R_2\) on the matrix gives

\(\left[\begin{array}{cc|c}5&5&5\\1&-\dfrac23&5\end{array}\right]\to\left[\begin{array}{cc|c}1&-\dfrac23&5\\5&5&5\end{array}\right]\)