Find x and the. RS and ST
Find x and the. RS and ST
(3x +1) + (2x -2) = 64
5x = 65
x = 13
RS = (3x +1) = (313) +1 = 40
ST = (2x -2) = (213) -2 = 24
SOLVING: (According to the image)
\(\overline{RS} + \overline{ST} = \overline{RT}\)
\((3x+1) + (2x-2)=64\)
3x + 1 + 2x - 2 = 64
3x + 2x = 64 - 1 + 2
5x = 65
\(x = \frac{65}{5}\)
\(\boxed{\boxed{x = 13}}\end{array}}\qquad\quad\checkmark\)