How do I solve: x/3 +10= 15
x/3+10=15
-10 -10
x/3= 5
x= 3*5
x=15
check by substitution 15/3 +10= 15
5+10=15, this is true
Therefore x=15 is the answer
\(\frac{x}{3}+10=15 \hbox{ /|10 (substract 10 from both) }\)
\(\frac{x}{3}=15-10=5\) ⇒ \(x=3*5\)
\(\boxed {x=15}\)