❌ Find the volume of the box ❌
10x^{3}+27x^{2}-48x+16
\(V=\underbrace{(x+4)(5x-4)}(2x-1)= \\ \\ = (5x^2+20x-4x-16)(2x-1) = (5x^2+16x -16)(2x-1)= \\ \\ 10x^3+32x^2 -32x -5x^2-16x +16 = \\ \\ =10x^3 +(32x^2-5x^2) +(-32x-16x) +16 = \\ \\ = \boxed{\bold{10x^3 +27x^2 -48x+16}}\)
