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When 10 grams of copper and 10 grams of iodine are mixed, what is the

theoretical yield of copper I iodide?

2Cu + I2 → 2CuI


30 grams


15 grams


7.5 grams


20 grams

Verified Answer :

The answer is B) 15 grams

sarajevo

Answer:

15 grams

Explanation:

Mass of Cu = 10 g  

Molar mass of Cu = 63.546 g/mol

Moles of Cu =\(\frac{10 g}{63.546 g/mol}\)  = 0.1574

Mass of I₂ = 10 g  

Molar mass of I₂ = 253.8 g/mol

Moles of I₂ = \(\frac{10 g}{253.8 g/mol }\) = 0.04

I₂ here is the limiting reactant as it has the least number of moles.  

Based on the balanced equation,

1 mole of I₂ = 2 moles of CuI

0.04 mole of I₂ = 0.08 moles of CuI

Molar mass of CuI = 190.45 g/mol

Mass of CuI = 0.08 moles x 190.45 g/mol  = 15.236  g

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