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While playing at the swimming pool, a 40-kilogram boy jumps off the side of the pool. When he hits the water, he is traveling 3 m/s. How much kinetic energy does he have right before he hits the water?



180 J


120 J


60 J


40 J

Verified Answer :

K.E. = mv² / 2
Here, m = 40 Kg
v = 3 m/s

Substitute their values, 
K.E. = 40 (3)² / 2
K.E. = 40 9 / 2
K.E. = 360/2
K.E. = 180 J

In short, Your Answer would be Option A

Hope this helps!

ferretgirl02

Kinetic energy= 1/2mv^2
m=40kg
v= 3m/s
K.E.=1/2 (40)(3)^2
K.E.=20× 9
K.E.=180 J

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