Answer: 28y^6/ 14y^4 = 2y^2
Step-by-step explanation:
The equation that we have is:
(28y^6)/(14y^4)
first, we can separate the scalars and the variables as:
(28y^6)/(14y^4) = (28/14)(y^6/y^4) = 2(y^6/y^4)
Now we can use the next thing:
a^n/a^m = a^(n - m)
2(y^6/y^4) = 2y^(6-4) = 2y^2
