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Find the quotient of the quantity negative 15 times x to the 2nd power times y to the 6th power plus 50 times x to the 4th power times y to the 3rd power minus 20 times x to the 2nd power times y all over 5 times x to the 2nd power times y.


−3y5 + 10x2y2 − 4

−15x2y6 + 50x4y3 − 4

3y5 + 10x2y2 − 4

−3xy5 + 10x2y2 − 4

Verified Answer :

Twistie

Evaluate (-15x^2y^6+50x^4y^3-20x^2y)/(5x^2y)
In shorter words, its a.

Answer:

\(3y^{5}+10x^{2}y^{2}-4\)

Step-by-step explanation:

We have to find the quotient of the quantity

\(\frac{15x^{2}y^{6}+50x^{4}y^{3}-20x^{2}y}{5x^{2}y}\)

= \(\frac{15x^{2}y^{6}}{5x^{2}y}+\frac{50x^{4}y^{3}}{5x^{2}y}-\frac{20x^{2}y}{5x^{2}y}\)

= \(3y^{5}+10x^{2}y^{2}-4\)

Therefore, \(3y^{5}+10x^{2}y^{2}-4\) is the quotient of the given expression.

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