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elska02
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A balloon holds 20.0 L of helium at 10 degree Celsius. If the temperature doubles, and the pressure does not change, what will be the new volume of the balloon? Using Charles's Law
Please help!

Verified Answer :

To solve this we assume
that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas
equation which is expressed as PV = nRT. At a constant pressure and number of
moles of the gas the ratio T/V is equal to some constant. At another set of
condition of temperature, the constant is still the same. Calculations are as
follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 2 x 20.0/ 1

V2 = 40 L