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Verified Answer :

diene

(a^2+b^2)^2
since (a+b)^2=a^2+2ab+b^2, substitute a with a^2 and b with b^2, which yields:
a^4+2(a^2*b^2)+b^4

\(( a^{2} + b^{2} )^{2}\)
 \(( a^{2} + b^{2} )( a^{2} + b^{2} )\)
\((a^{4}+a^{2}b^{2}+a^{2}b^{2}+b^{4})\)
\((a^{4}+2a^{2}b^{2}+b^{4})\)

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