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Consider a set of 7500 scores on a national test whose score is known to be distributed normally with a mean of 510 and a standard deviation of 85. About how many scores greater than 600 would we expect to find?

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LammettHash

\(\mathbb P(X>600)=\mathbb P\left(\dfrac{X-510}{85}>\dfrac{600-510}{85}\right)=\mathbb P(Z>1.059)\approx0.145\)

So approximately 14.5% of the scores are higher than 600. This means in a sample of 7500, one could expect to see \(0.145\times7500\approx10.86\) scores above 600.

chibu

Answer:

1086

Step-by-step explanation:

Ap3X

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