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Which polynomial will definitely have nonreal zeros?

Hint: Use Descartes's rule of signs.

x3 − 2x2 − x − 2

x3 − 2x2 + x − 2

x4 + 8x2 + 16

x4 − 8x2 + 16

Verified Answer :

MissPhiladelphia

The best and most correct answer among the choices provided by the question is the second choice. The polynomial that will definitely have non-real zeroes would be x3 − 2x2 + x − 2, and it can be solved using the Descartes's rule of signs. I hope my answer has come to your help. God bless and have a nice day ahead!