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A skydiver jumps from an airplane and falls freely for 5 seconds. If the sky diver's velocity increases by 49 m/s during that time, at which rate is the diver accelerating ?

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Katelynn05

Your answer would be 9.8

AL2006


Acceleration  =  (change in speed)  /  (time for the change)

                       =      (49 m/s)   /   (5 seconds)

                       =       (49 / 5)  m/s  /  s

                       =            9.8 m/s² 

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