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CarlaL
CarlaL CarlaL
  • 10-01-2017
  • Chemistry
Answered

9.86 x 10²⁸ O-atoms require what volume (L) N₂O₂ at STP?

Verified Answer :

MissPhiladelphia
MissPhiladelphia MissPhiladelphia
  • 11-01-2017

First, we use avogadro's number to convert atoms into moles. Then, relate the number of moles from elemental to the compound. Lastly, we use conditions at STP to calculate the volume. We do as follows:

9.86 x 10²⁸ O-atoms ( 1 mol / 6.022x10^23 atoms O) ( 1 mol N2O2 / 2 mol O ) ( 22.4 L / 1 mol ) = 1833809.37 L needed

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