answer is a for both questions
\(x^2=75\)
Inverse of squared is square root. \(x= \sqrt{75}\)
\(x= \sqrt{25*3}\)
\(x=5 \sqrt{3}\)
\(x^3=16\)
\(x= \sqrt[3]{2*2*2*2}\) prime factorization of 16
\(x=2 \sqrt[3]{2}\) a set of 3 comes out as one number...i.e. 2
