22nd term: a1=5,d=4????
22nd term: a1=5,d=4????
The formula for arithmetic sequences is
a\/n= a\/1 + (n-1)d,
and n represents # of terms
With the information, we can make the equation:
a\/n= 5 + (n-1)(4) .
Then, since n= 22 in this particular problem, we can plug that number in.
a\/22 = 5 + (22-1)(4)
a\/22 = 5 + (21)(4)
a\/22 = 5 + (84)
a\/22 = 89
In conclusion, 89 is the value of the 22nd term
a1=5, =41+1 d=4
a2=5+4=9=42+1
a3=9+4=13=43+1
a4=13+4=17=44+1
a5=17+4=21=45+1
...
a22=422+1=83
do you see the mistake