devin804 devin804

05-01-2017
Mathematics

Answered

Find the distance between points P(1, 2) and Q(4, 8) to the nearest tenth. 11.2 5 6.7 9

Verified Answer :

texaschic101 texaschic101

05-01-2017

distance = sqrt (x2 - x1)^2 + (y2 - y1)^2
(1,2)...x1 and y1
(4,8)...x2 and y2
now we sub
distance = sqrt (4 - 1)^2 + (8 - 2)^2
distance = sqrt (3^2 + 6^2)
distance = sqrt (9 + 36)
distance = sqrt (45)
distance = 6.7 <===

Answer Link

golden123 golden123

05-01-2017

PQ=√(x2-x1)²+(y2-y1)²
   =√(4-1)²+(8-2)²
   =√(3)²+(6)²
   =√9+36
   =√45
   =3√5
   =3*2.236
   =6.708
   =6.79.

Answer Link

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