if (x+2) is a factor of x^3-6x^2+kx+10, k=
If a binomial \((x-a)\) is a factor of a polynomial, then \(a\) is a root of this polynomial.\((x+2)=(x-(-2)) \Rightarrow a=-2\\\\ (-2)^3-6\cdot(-2)^2+k\cdot(-2)+10=0\\ -8-24-2k+10=0\\ -2k=22\\\ \boxed{k=-11}\)
Answer:
k=-11
Step-by-step explanation:
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