ok, so from previous question
(x-h)^2=4p(y-k)
distance from focus to directix is 2
2/2=1=p
1>-1
focus is above the vertex
1 unit down from (0,1) is (0,0)
vertex at (0,0)
since focus is above, p is positive
(x-0)^2=4(1)(y-0)
x^2=4y
4y=x^2
divide both sides by 4
y=(1/4)x^2
f(x)=1/4x^2
2nd one is answer
