A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCl. What volume of 3.00 M HCl did the student use to make the sample? Use mc020-1.jpg. 3.70 mL 16.7 mL 30.0 mL 83.3 mL
Answer is 30.0mL
according to the question dilution is performed by the student which can be calculated with the help of :
\(M_{1}V_{1}=M_{2}V_{2}\) EQUATION (1)
Here, we have:
\(M_{1}\) = 3M
\(V_{1}\) = y mL
\(M_{2}\)= 1.80 M
\(V_{2}\) = 50.0mL
putting the known values in equation (1) which will give us value of \(V_{1}\)
3.00× y =1.80 ×50.0
y= 30.0mL