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Isolate sin(x) by adding 4 and taking the square root of both sides.
State that sin(x) = 2 or sin(x) = –2.State that –2 and 2 are undefined values  of the inverse sine function.There are no solutions because –2 and 2 are not in the domain of the function.

Answer:

No, the given equation:

\(\sin^2x-4=0\)

does not have any solution.

Step-by-step explanation:

\(sin^2x-4=0\\\\this\ means\ that\\\\(sinx-2)(sinx+2)=0\\\\so\ either\ sinx-2=0 or\ sinx+2=0\\\\i.e. sinx=2 or\ sinx=-2\\\\but\ this\ is\ not\ true\ as\ value\ of\ sinx\ lies\ between\ -1\ and\ 1\)

Hence, the given equation:

\(\sin^2x-4=0\) does not have any solution.

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